Menu
Popular Courses
Search
Question

The price of sugar having gone down by 10%, sharad can buy 6.2 kg more for Rs. 279. The difference  between the

original and the reduced price(per kg ) is :


Options:
A .  Re. 0.50
B .  Re. 1
C .  Rs.1.50
D .  Rs.4.50
Answer: Option A

Let original price =  Rs. `x` per kg. Reduced  price  = Rs. `((90x)/(100))` per kg

`:.`    `(279)/((90x)/(100)) - 279/x =  6.2   hArr   (27900)/(90x) -  279/x` =  6.2

                                                         `hArr 27900 - 25110 =  6.2 xx 90x`

                                                         `hArr   558x =   2790     hArr   x = 5`

`:.`       Required difference  =       10%  of Rs. 5 =  Re.   0.50




Was this answer helpful ?
Next Question

Submit Comment/FeedBack

Your email address will not be published. Required fields are marked *

Share this page with your friends!

Latest Videos

Chapter 1 - GLOBAL STEEL SCENARIO & INDI Part 1 : (13-04-2024) INDUSTRY AND COMPANY AWARENESS (ICA)
Direction Sense Test Part 1 Reasoning (Hindi)
Chapter 1 - RMHP / OHP / OB & BP Part 1 : (14-02-2024) GPOE
Cube & Cuboid Part 1 Reasoning (Hindi)
Data Interpretation (DI) Basic Concept Reasoning (Hindi)
Counting Figures Part 1 Counting Of Straight Lines Reasoning (Hindi)
Real Numbers Part 7 Class 10 Maths
Real Numbers Part 1 Class 10 Maths
Polynomials Part 1 Class 10 Maths

Latest Test Papers

Chapter 3.1 : Overview of Finance & Acco Chapter 3 : Finance & Accounts SAIL E0 - GFM 2024
Chapter 2.1 : Overview Chapter 2 : Materials Management SAIL E0 - GFM 2024
Chapter 1.1 : Personnel Functions- An ov Chapter 1 : Personnel Management SAIL E0 - GFM 2024
GPOE / GPA Combined 1 Free CBT Mock Test SAIL E0 2024
CBT Mixed Test 1 GPOE/GPA SAIL E0 2024