The price of an article was increased by r%. Later the new price was decreased by r % if the latest price was
Re. 1, then the original price was :
Let the original price be Rs. `x`
`:.` (100 - r)% of (100 + r)% of `x` = 1
`rArr ((100 - r))/(100) xx ((100 + r))/(100) xx x = 1`
`rArr x = (100 xx 100)/((100 - r) (100 + r))`
= `(10000)/((10000 - r^2))`
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