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The population of a town is 40,000. It decreases by 20 per thousand per year. Find out the population after 2 years.
Options:
A .  38484
B .  38266
C .  38416
D .  38226
Answer: Option C

Answer : Option C

Explanation :

This problem is similar to the problems we saw in compound interest. We can use the formulas of compound interest here as well.
In compound interest, interest (a certain percentage of the principal) will be added to the principal after every year. Similarly, in this problem, a certain count(a certain percentage of the population) will be decreased from the total population after every year
$MF#%\text{i.e., the formula becomes, A = }\text{P}\left(1 - \dfrac{\text{R}}{100}\right)^\text{T}$MF#%

where Initial population = P, Rate = R% per annum, Time = T years and A = the population after T years
Please note that we have to use the -ve sign here instead of the + sign as the population gets decreased


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