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The population of a town increased from 1,75,000 to 2,62,500 in a decade. What is the average percent increase of population per year?
Options:
A .  4%
B .  6%
C .  5%
D .  50%
Answer: Option C

Answer : Option C

Explanation :

Increase in the population in 10 years = 2,62,500 - 1,75,000 = 87500

$MF#%\begin{align}
&\text{% ncrease in the population in 10 years = }\dfrac{87500}{175000}\times 100 = \dfrac{8750}{175}=50\% \\
&\text{Average % increase of population per year = }\dfrac{50\%}{10} = 5\%
\end{align} $MF#%



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