The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of he areas of the two squares.
Side of first square = `(40/4)` cm = 10 cm.
Side of second square =`(32/4)` cm = 8 cm.
Area of third square =` [(10)^2 - (8)^2] cm^2` = (100 - 64) `cm^2` = 36`cm^2`
Side of third square = `sqrt(36)` = 6 cm.
`:.` Required perimeter = (6 x 4) cm = 24 cm.
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