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The perimeters of five squares are 24 cm, 32 cm , 40 cm, 76 cm and 80 cm respectively . The perimeter of another square equal in area to the sum of the area of these squares is :


Options:
A .  31 cm
B .  62 cm
C .  124 cm
D .  961 cm
Answer: Option C

The sides of the five squares are `(24/4), (32/4), (40/4), (76/4), (80/4)   i.e.  6 cm, 8 cm, 10 cm, 19 cm, 20 cm.

`:.`     Area of the square = `[6^2 + 8^2 + (10)^2 + (19)^2 + (20)^2`]

= ( 36 + 64 + 100 + 361 + 400) `cm^`

= 961 `cm^2`

Side of the new square = `sqrt(961)` =  31 cm.

perimeter of the new square  = (4 x 31) cm =  124 cm.



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