Answer: Option D
Let the sides of the triangle be 5x, 5x and 4x cm respectively
Then,
5x + 5x = 4x + 14
⇒ 14 x = 14
⇒ x = 1
So, a = 5 cm, b = 5 cm, c = 4 cm
$$\eqalign{
& s = \frac{{{\text{a + b + c}}}}{2} \cr
& \,\,\,\,\,\,\,\, = \left( {\frac{{14}}{2}} \right)cm \cr
& \,\,\,\,\,\,\,\, = 7cm \cr} $$
(s - a) = 2 cm, (s - b) = 2 cm, (s - c) = 3 cm
∴ Area of the triangle :
$$\eqalign{
& = \sqrt {7 \times 2 \times 2 \times 3} \cr
& = 2\sqrt {21} \,c{m^2} \cr} $$