Question
The order of the differential equation whose general solution is given by y=C1e2x+C2+C3ex+C4sin(x+C5) is
Answer: Option B
:
B
y=C1e2x+C2+C3ex+C4sin(x+C5)=C1.eC2e2x+C3ex+C4(sinxcosC5+cosxsinC5)=Ae2x+C3ex+Bsinx+Dcosx
Here, A=C1eC2,B=C4cosC5,D=C4sinC5
(Since equation consists of four arbitrary constants)
∴ order of differential equation = 4.
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B
y=C1e2x+C2+C3ex+C4sin(x+C5)=C1.eC2e2x+C3ex+C4(sinxcosC5+cosxsinC5)=Ae2x+C3ex+Bsinx+Dcosx
Here, A=C1eC2,B=C4cosC5,D=C4sinC5
(Since equation consists of four arbitrary constants)
∴ order of differential equation = 4.
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