Question
The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu. The binding energy of the helium nucleus will be [1 amu= 931 MeV]
Answer: Option A
:
A
Helium nucleus consist of two neutrons and two protons.
So binding energy E=Δm×931MeV
⇒E=(2×mp+2mn−M)×931MeV=(2×1.0073+2×1.0087−4.0015)×931=28.4MeV
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:
A
Helium nucleus consist of two neutrons and two protons.
So binding energy E=Δm×931MeV
⇒E=(2×mp+2mn−M)×931MeV=(2×1.0073+2×1.0087−4.0015)×931=28.4MeV
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