Question
The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hours is
(Velocity of light =3×108m/s )
(Velocity of light =3×108m/s )
Answer: Option D
:
D
E=Δm.c2⇒E=0.31000×(3×108)2=2.7×1013J
=2.7×10133.6×106=7.5×106kWh.
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:
D
E=Δm.c2⇒E=0.31000×(3×108)2=2.7×1013J
=2.7×10133.6×106=7.5×106kWh.
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