Let the length be x metres and breadth be y metres
Then it's area =(xy)m2
New length =(125/100 x)m =(5x/4)m.
Let the new breadth be 2 metres
Then xy 5x/4 x 2 => 2 = 4/5 y
Decreased in width =(y -4/5 y) = y/5 metres
Decreased % in width =(y/5 x 1/y x 100)% = 20%
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