The length of a rectangle is three times of its width . If the length of the diagonal is `8sqrt(10)` cm. then the perimeter of the rectangle is :
Let breadth = `x` cm., Then , length = `3x` cm.
`x^2 + (3x)^2 = (8sqrt(10))^2`
`rArr 10x^2 = 640`
`rArr x^2 = 64 `
`rArr x = 8`
So , length = 24 cm and breadth = 8 cm.
`:.` perimeter = [2 (24 + 8)] cm = 64 cm.
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