The length of a rectangle is increased by 60% , by what percent would the width have to be decreased so as to maintain the same area
Let original length = `x` and original breadth = y.
Then , original area = `xy`
New length = `(160x)/(100)= (8x)/(5)` , Let new breadth = z.
Then , `(8x)/(5) xx z = xy`
`rArr z = (5y)/(8)`
`:.` Decrease in breadth = `((3y)/(8) xx 1/y xx 100)`% = `37 1/2`%
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