The length of a rectangle is 20% more than its breadth . What will be the ratio of the area of a rectangle to that of a square whose side is equal to the breadth of the rectangle ?
Let breadth be `x` metres. Then , length = 120% of ` x = (120/100 x) = (6x)/(5)` m.
Required ratio = `((6x)/(5) xx x xx (1)/(x xx x))` = 6 : 5
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