The length and breadth of a square are increased by 40% and 30% respectively . The area of resulting exceeds he area of the square by :
Let length = l metres and breadth = b metres.
Then original area = (lb) `m^2`
New length = (140% of l) m = `(140/100 xx l)m = (7l)/(5)` m
New breadth = (130% of b)m = `(130/100 xx b) m = (13b)/(10)` m
New area = `((7l)/(5) xx (13l)/(10)) = (91/50 lb)m^2`
Increase = `(91/50 lb - lb) = 41/50 lb`
`:.` Increase % = `(41/50 xx lb xx (1)/(lb) xx 100)`% = 82%
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