The least perfect square number divisible by 3, 4, 5, 6 and 8 is = ?
Options:
A . 900
B . 1200
C . 2500
D . 3600
Answer: Option D L.C.M. of 3, 4, 5, 6, 8 is 120 Now 120 = 2 × 2 × 2 × 3 × 5 To make it a perfect square, it must be multiplied by 2 × 3 × 5 So, required number $$\eqalign{ & = {2^2} \times {2^2} \times {3^2} \times {5^2} \cr & = 3600 \cr} $$
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