Question
Answer: Option B
:
B
Decide the parent chain and give the numbering so that more substituted substituent will get the least number.
parent chain
10 carbons ⇒ word root ⇒ dec
single bond ⇒ suffix ⇒ ane
substituents at C5andC2
Now,
There is one more same substituent on C5
Therefore,
5,5-Bis-(1,1-dimethyl propyl)
Bis⇒ Because two same substituents are there, and a methyl group at C2⇒ 2-methyl
Therefore,
5,5-Bis-(1,1-dimethylpropyl)-2-methyldecane
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:
B
Decide the parent chain and give the numbering so that more substituted substituent will get the least number.
parent chain
10 carbons ⇒ word root ⇒ dec
single bond ⇒ suffix ⇒ ane
substituents at C5andC2
Now,
There is one more same substituent on C5
Therefore,
5,5-Bis-(1,1-dimethyl propyl)
Bis⇒ Because two same substituents are there, and a methyl group at C2⇒ 2-methyl
Therefore,
5,5-Bis-(1,1-dimethylpropyl)-2-methyldecane
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