The dimensions of a certain machine are 48" × 30" × 52". If the size of the machine is increased proportionately until the sum of its dimensions equal 156", what will be the increase in the shortest side ?
Options:
A . 4"
B . 6"
C . 8"
D . 9"
Answer: Option B Sum of original dimension : $$\eqalign{ & = 48 + 30 + 52 \cr & = 130 \cr} $$ Increase in sum : $$\eqalign{ & = 156 - 130 \cr & = 26 \cr} $$ Since the dimensions have been increased proportionately, So increase in shortest side : $$ = \left( {26 \times \frac{{30}}{{130}}} \right)$$ " $$ = 6$$ "
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