The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
Options:
A . 20 , 30
B . 27 , 23
C . 29 , 21
D . 31 , 19
Answer: Option B
Let the two parallel sides of the trapezium be a cm and b cm. Then, a - b = 4 And, (1/2) x (a + b) x 19 = 475 (a + b) = ((475 x 2)/19) a + b = 50 Solving (i) and (ii), we get: a = 27, b = 23 So, the two parallel sides are 27 cm and 23 cm.
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