The difference between two parallel sides of a trapezium is 4 cm. The perpendicular distance between them is 19 cm . If the area of the trapezium is 475 `cm^2` . Find the lengths of the parallel sides .
Let the two parallel sides of the trapezium be a cm. and b cm.
Then , a - b = 4. .......................................(i)
And , `1/2 xx (a + b) xx 19 = 475`
`hArr (a + b) = ((475 xx 2)/(19))`
`hArr (a + b) = 50 ...........................................(ii)
Solving (i) and (ii) , we get : a = 27, b = 23.
So the two parallel sides are 27 cm and 23 cm.
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