The difference between two numbers is 3 and the difference between their squares is 63. Which is the larger number ?
Options:
A . 9
B . 12
C . 15
D . Cannot be determined
E . None of these
Answer: Option B Let the number be x and y Then, $${x^2} - {y^2} = 63\,\,\,\,\& \,\,\,\,x - y = 3$$ On dividing, we get: x + y = 21 Solving x + y = 21 and x - y = 3, We get: x = 12 and y = 9 ∴ Larger number = 12
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