Let the sum be Rs x.
Then
S. I = Rs (x × 8/100 × 2) = Rs 4x/25
C. I = Rs [x × (1 + 8/100)2 - x]
= Rs (x × 27/25 × 27/25 - x)
=Rs 104x/625
(C.I) “ (S.I)
= Rs(104x/625 “ 4x /25)
= Rs 4x /625
Therefore 4x/625 = 768
=> x = ((768 ×625)/4) = 120000
Therefore sum = Rs 120000
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