The correct sequence of decrease in the bond angles of the following hydrides is Options: A . &nbsp N H 3 > P H 3 > A s H 3 > S b H 3 B . &nbsp N H 3 > A s H 3 > P H 3 > S b H 3 C . &nbsp S b H 3 > A s H 3 > P H 3 > N H 3 D . &nbsp P H 3 > N H 3 > A s H 3 > S b H 3

The correct sequence of decrease in the bond angles of the following hydrides

Question

The correct sequence of decrease in the bond angles of the following hydrides is

Options:

A .

N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

B .

N H_{3} > A s H_{3} > P H_{3} > S b H_{3}

C .

S b H_{3} > A s H_{3} > P H_{3} > N H_{3}

D .

P H_{3} > N H_{3} > A s H_{3} > S b H_{3}

Answer: Option A
:
A

N H_{3}

has

s p^{3}

hybridisation with bond angle

107^{0}

where as

P H_{3}, A s H_{3}, S b H_{3}

has pure orbitals overlapping with bond angle around

90^{0}

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