Answer : Option B

Explanation :

Let the period be n years
Then, amount after n years = Rs.(30000 + 4347) = Rs. 34347
$MF#%\begin{align}&\text{P}\left(1 + \dfrac{\text{R}}{100}\right)^\text{T} = 34347\\\\ &30000\left(1 + \dfrac{7}{100}\right)^\text{n} = 34347\\\\ &30000\left(\dfrac{107}{100}\right)^\text{n} = 34347\\\\ &\left(\dfrac{107}{100}\right)^\text{n} = \dfrac{34347}{30000} = \dfrac{11449}{10000} = \left(\dfrac{107}{100}\right)^2\\\\ &n = 2\text{ years}\end{align}$MF#%