The batting average for 40 innings of a cricket player is 50 runs. His highest score
exceeds his lowest score by 172 runs. If these two innings are excluded, the average of
the remaining 38 innings is 48 runs. Find out the highest score of the player.
Total runs scored by the player in 40 innings = 40×50
Total runs scored by the player in 38 innings after excluding two innings 38×48
Sum of the scores of the excluded innings = 40×50−38×48=2000−1824=176
Given that the scores of the excluded innings differ by 172.
Hence let's take
the highest score as x + 172 and lowest score as x
Now x + 172 + x = 176
=> 2x = 4
=>x=4/2=2
highest score as x + 172 = 2 + 172 = 174
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