The batting average for 40 innings of a cricket player is 50 runs. His highest score exceed his lowest score by
172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is :
Let the highest score be `x`. Then ,lowest sore= (`x` - 172)
Then , (50 x 40) - [`x + (x` - 172)] = 38 x 48
`hArr` `2x` = 2000 + 172 - 1824 `hArr` `2x` = 348 `hArr` `x` = 174.
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