The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is
Options:
A . 170
B . 174
C . 165
D . 172
Answer: Option B Answer: (b) Let the highest score of cricketer be x runs. ∴ His lowest score = (x – 172) runs According to the question, 38 × 48 + x + x – 172 = 40 × 50 ⇒ 1824 – 172 + 2x = 2000 ⇒ 1652 + 2x = 2000 ⇒ 2x = 2000 – 1652 = 348 ∴ x = 348 2 = 174 runs
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