The batting average for 40 innings of a cricket palyer is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is
Options:
A . 165 runs
B . 170 runs
C . 172 runs
D . 174 runs
Answer: Option D
Let the highest score be x. Then, lowest score =(x-172) =[(50 x 40)-(x+(x-172)] =38 x 48 2x=2000+172-1824 2x=348 x=174.
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