The average run of a player is 32 out of 10 innings. How many runs must he make in the next innings so as to increase his average by 6 ?
Options:
A .  40
B .  98
C .  38
D .  6
Answer: Option B Answer: (b)Runs scored in the next innings = x (let) According to the question, 10 × 32 + x = 11 × 38 ⇒ 320 + x = 418 ⇒ x = 418 – 320 = 98 Aliter : Using Rule 18, If in the group of N persons, a new person comes at the place of a person of 'T’ years, so that average age, increases by 't’ years Then, the age of the new person = T + N.t. Here, T = 32, N= (10 + 1) = 11, t = 6 Required Runs = T + Nt = 32 + 11 × 6 = 32 + 66 = 98
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