The average of then two-digit numbers , which remain the same when the digits inter -change their positions, is :
Average = `((11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99)/(9))`
= `[((11 + 99) + (22 + 88) + (33 + 77) +( 44 + 66) + 55)/(9)]`
= `((4xx 110 + 55)/(9))` = ` 495/9` = 55.
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