The average of the squares of first ten natural numbers is Options: A . &nbsp38.5 B . &nbsp37.5 C . &nbsp36 D . &nbsp35.5

The average of the squares of first ten natural numbers is

Question

The average of the squares of first ten natural numbers is

Options:

A . 38.5

B . 37.5

C . 36

D . 35.5

Answer: Option A
Answer: (a)Using Rule 4,Average of $1^2,2^2,3^2,4^2…x^2$ = ${(n+1)(2n+1)}/6$${1^2+2^2+3^2+…+n^2}/n$ = ${(n+1)(2n+1)}/6$∴ ${1^2+2^2+3^2+…+10^2}/10$ = ${(10+1)(2×10+1)}/6$= ${11×21}/6$ = 38.5

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