The average of the largest and smallest 3 digit numbers formed by 0, 2 and 4 would be
Options:
A .  213
B .  303
C .  222
D .  312
Answer: Option D Answer: (d)Largest 3–digit number formed by 0, 2 and 4 = 420 Smallest number of three digits = 204 ∴ Required average = ${420+204}/2$ = $624/2$ = 312
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