Question
The average of temperatures at noontime from Tuesday to Saturday is 50; the lowest one is 45, what can be the possible maximum range of the temperatures.
Answer: Option B
:
B
The average of the 5 temperatures is: a+b+c+d+e5=50
One of these temps is 45: a+b+c+d+455=50.
Solving for the variables: a + b + c + d = 205
In order to find the greatest range of temps, we minimize all temps but one. Remember, though, that 45 is the lowest temp possible, so: 45 + 45 + 45 + d = 205 Solving for the variable: d = 70
70 - 45 = 25 Option (b).
2nd method:-For finding maximum range, we will take 4 days minimum out of 5 days i.e 4 days temp. will take 45, then total negative deviations will be 20. Thus for average 50, positive deviation should be also 20 . Thus highest temp will be (50+20)=70 degrees. Then range =70-45 = 25. Option (b).
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:
B
The average of the 5 temperatures is: a+b+c+d+e5=50
One of these temps is 45: a+b+c+d+455=50.
Solving for the variables: a + b + c + d = 205
In order to find the greatest range of temps, we minimize all temps but one. Remember, though, that 45 is the lowest temp possible, so: 45 + 45 + 45 + d = 205 Solving for the variable: d = 70
70 - 45 = 25 Option (b).
2nd method:-For finding maximum range, we will take 4 days minimum out of 5 days i.e 4 days temp. will take 45, then total negative deviations will be 20. Thus for average 50, positive deviation should be also 20 . Thus highest temp will be (50+20)=70 degrees. Then range =70-45 = 25. Option (b).
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