The average of nine consecutive numbers is n. If the next two numbers are also included the new average will
Options:
A . increase by 1
B . increase by 1.5
C . remain the same
D . increase by 2
Answer: Option A Answer: (a) Fifth number = n Tenth number = n + 5 Eleventh number = n + 6 New average = ${9n+n+5+n+6}/11$ = ${11n+11}/11$ = ${(n+1) ×11}/11$ = n+1
Submit Comment/FeedBack