The average of 9 integers is found to be 11. But after the calculation, it was detected that, by mistake, the integer 23 was copied as 32, while calculating the average. After the due correction is made, the new average will be
Options:
A . 9
B . 10
C . 9.5
D . 10.1
Answer: Option B Answer: (b)Sum of 9 integers = 9 × 11 = 99. New average = ${90+ 23- 32}/9$ = $90/9$ =10 Aliter : Using Rule 26,The correct average will be = m +${\text"(a-b)"}/ \text"n"$.Here, n = 9, m = 11 a = 23, b = 32 Correct mean = m + ${\text"(a - b)"}/\text"n"$= 11 +${(23 -32)}/9$= 11 +${(-9)}/9$= 11 – 1 = 10
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