The average of 5 consecutive integers starting with ‘m’ is n. What is the average of 6 consecutive integers starting with (m + 2) ?
Options:
A . $\text"2n+5"/2$
B . $n+2$
C . $n+3$
D . $\text"2n+9"/2$
Answer: Option A Answer: (a) According to the question let m = 1 ∴ 5 consecutive integers are = 1,2,3,4,5 $\text"1+2+3+4+5"/5=n$ $n = 15/5=3$ 6 consecutive integers starting with (m + 2) are = 3,4,5,6,7,8 ∴$\text"3+4+5+6+7+8"/6=33/6=11/2$ Now check from option to put n = 3 While in Option :(a) $\text"2n+5"/2 = 11/2 $
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