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The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?
Options:
A .  1
B .  20
C .  0
D .  19
Answer: Option D

Answer : Option D

Explanation :

Average of 20 numbers = 0
$MF#%=> \dfrac{\text{Sum of 20 numbers}}{20} = 0$MF#%
=> Sum of 20 numbers = 0
Hence at the most, there can be 19 positive numbers.
(Such that if the sum of these 19 positive numbers is x, 20th number will be -x)



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