The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average one number, namely 36, was wrongly read as 26. The correct average is
Options:
A . 18
B . 20
C . 14
D . 16
Answer: Option D Answer: (d)Correct total of 10 numbers = 15 × 10 – 26 + 36 = 160 ∴ Correct average = $160/10$ = 16 Aliter : Using Rule 26,If average of n numbers is m later on it was found that a number 'a’ was misread as 'b’. The correct average will be = m +${\text"(a-b)"}/ \text"n"$.Here, n = 10, m =15 a = 36, b = 26 Correct Average = m + ${\text"(a - b)"}/\text"n"$ = 15 +${(36 – 26)}/10$= 15 + 1 = 16
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