The areas of two similar triangles are 12 cm2 and 48SQ. cm .If the height of the smaller one is 2.1cm than the corresponding height of the bigger one is
Options:
A . 0.525cm
B . 4.2cm
C . 80%
D . 60%
Answer: Option D
The area of two similar triangles is the ratio of the square of the corresponding heights. Therefore , 12/48 = (2.1)2 /h2 => h2 = 4 x (2.1)2 => h=(2 x 2.1)=4.2 cm
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