The angle of elevation of the top of a tower at a point on the ground 50 m away

Question

The angle of elevation of the top of a tower at a point on the ground 50 m away from the foot of the tower is 45°. Then the height of the tower (in metres) is

Options:

A . $$50\sqrt 3 $$

B . $$50$$

C . $$\frac{{50}}{{\sqrt 2 }}$$

D . $$\frac{{50}}{{\sqrt 3 }}$$

Answer: Option B

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