Sum of the first 30 terms of an arithmetic progression is 0. If the first term is -29, then find the sum of the 28th, 29th and 30th terms of this arithmetic progression.

Let the common difference of the arithmetic progression be 'd'. Sum of first 30 terms of the arithmetic progression =302×[2(−29)+(30−1)d] Hence, 15(−58+29d) = 0 Hence, d=2 Sum of 28th, 29th and 30th term of this arithmetic progression = 3(-29) + (27 + 28 +29) × 2 = 81

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