Question
Solution to the differential equation x+x33!+x55!+.....1+x22!+x44!+.....=dx−dydx+dy is
Answer: Option B
:
B
Applying C and D, we get
dydx=e−xex=e−2x⇒2y=−e−2x+C
or 2ye2x=C.e2x−1.
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B
Applying C and D, we get
dydx=e−xex=e−2x⇒2y=−e−2x+C
or 2ye2x=C.e2x−1.
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