Answer: Option C
let l, b and h denote the length, breadth and depth of Meeta's lunch box
Then, length of Rita's lunch box :
$$ = 110\% {\text{ of }}l = \frac{{11l}}{{10}}$$
Breadth of Rita's lunch box :
$$ = 110\% {\text{ of }}b = \frac{{11b}}{{10}}$$
Depth of Rita's lunch box :
$$ = 80\% {\text{ of }}h = \frac{{4h}}{5}$$
∴ Ratio of the capacities of Rita's and Meeta's lunch boxes :
$$\eqalign{
& = \frac{{11l}}{{10}} \times \frac{{11b}}{{10}} \times \frac{{4h}}{5}:lbh \cr
& = \frac{{121}}{{125}}:1 \cr
& = 121:125 \cr} $$