Question
Ratio of Henry’s constant, KH of two inert gases A & B is 2 at a given temperature. A mixture containing 4 moles of gas A and 8 moles of gas B is bubbled through water covered from top and solution is allowed to attain equilibrium. Assuming the absence of any other gases, what will be the ratio of mole fractions of gases in the solution.
Answer: Option B
:
B
Let ‘a’ and ‘b’ moles of gases dissolve in water while rest accumulates over the solution to create partial pressure.
From Henry’s Law –
p=KHX
⇒p1P2=KH1KH2×X1X2
⇒4−a8−b=12×ab
⇒4−a/b8−1=12×ab
⇒ab=4×29=89
Hence Answer is option (b)
Was this answer helpful ?
:
B
Let ‘a’ and ‘b’ moles of gases dissolve in water while rest accumulates over the solution to create partial pressure.
From Henry’s Law –
p=KHX
⇒p1P2=KH1KH2×X1X2
⇒4−a8−b=12×ab
⇒4−a/b8−1=12×ab
⇒ab=4×29=89
Hence Answer is option (b)
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution