One of the two events must occur. If the chance of one is 23 of the other,

Question

One of the two events must occur. If the chance of one is

\frac{2}{3}

of the other, then odds in favour of the other are

Options:

A . 2:3

B . 1:3

C . 3:1

D . 3:2

Answer: Option D
:
D
Let p be the probability of the other event, then the probability of the first event is

\frac{2}{3}

p. Since two events are totally exclusive, we have

p + (\frac{2}{3}) p = 1 \Rightarrow p = \frac{3}{5}

Hence odds in favour of the other are 3 : 5 – 3, i.e, 3 : 2.

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