## Solutions

Question

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: D

M1V1=M2V2

whereV1=1litre,M1=1m

V2=1+5=6litre,M2=?

thus,

1×1=6×M2

M2=16 [′n′factorofH2SO4=2]

But normality='n' factor × molarity = 2 × 16=13

N=13

One litre of 1 molar H2SO4 solution has been diluted by 5 litre water, the normality of the solution is

**Options:**

A. | 0.2N |

B. | 5N |

C. | 10N |

D. | 0.33N |

**Answer: Option D**

: D

M1V1=M2V2

whereV1=1litre,M1=1m

V2=1+5=6litre,M2=?

thus,

1×1=6×M2

M2=16 [′n′factorofH2SO4=2]

But normality='n' factor × molarity = 2 × 16=13

N=13

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