Answer : Option A
Explanation :
Given that height on 15th birthday = 159 cm and growth = 6%
Let the previous year height = x
$MF#%\begin{align}&\text{Then height on 15th birthday = }x \times \dfrac{\left(100 + 6\right)}{100} = x \times \dfrac{106}{100}\\
&\Rightarrow 159 = x \times \dfrac{106}{100}\\
&\Rightarrow x = \dfrac{159 \times 100}{106} = 1.5 \times 100 = 150\text{ cm}\end{align} $MF#%
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