Of the three numbers, first is twice the second and second is twice the third. The average of three numbers is 21. The smallest of the three numbers is
Options:
A .  12
B .  18
C .  9
D .  6
Answer: Option C Answer: (c)Let the third number be x. ∴ The second number = 2x and the third number = 2 × 2x = 4x According to the question, ${4x+2x+x}/3$ = 21⇒ 7x = 21 × 3 ⇒ x =${21×3}/7$ = 9 Aliter : Using Rule 15, From three numbers, first number is 'a’ times of 2nd number, 2nd number is 'b’ times of 3rd number and the average of all three numbers is x, then, First number = $\text"3ab"/ \text"1+b+ab"$ x ; Second number = $\text"3b"/ \text"1+b+ab"$ x ; Third number = $\text"3b"/ \text"1+b+ab"$ x a = 2, b = 2, x = 21 First number = $\text"3ab"/ \text"1+b+ab"$x= ${3×2×2}/{1+2+4}$×21= $12/7$×21=36Second number = $\text"3ab"/ \text"1+a+ab"$x = ${3×2}/7$×21 = 18Third number = $3/ \text"1+a+ab"$x = $3/7$×21 = 9
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