Answer : Option D
Explanation :
$MF#%4.\overline{86} = \left(4 + \dfrac{86}{99}\right)$MF#%
$MF#%3.\overline{95} = \left(3 + \dfrac{95}{99}\right)$MF#%
$MF#%\text{Hence, }4.\overline{86} - 3.\overline{95} = \left(4 + \dfrac{86}{99}\right) - \left(3 + \dfrac{95}{99}\right)
= \left( 1 - \dfrac{9}{99}\right) = \dfrac{90}{99} = 0.\overline{90}$MF#%
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