Answer : Option D
Explanation :
$MF#%4.\overline{86} = \left(4 + \dfrac{86}{99}\right)$MF#%
$MF#%3.\overline{71} = \left(3 + \dfrac{71}{99}\right)$MF#%
$MF#%\text{Hence, }4.\overline{86} - 3.\overline{71} = \left(4 + \dfrac{86}{99}\right) - \left(3 + \dfrac{71}{99}\right)
= \left( 1 + \dfrac{15}{99}\right) = 1.\overline{15}$MF#%
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